In Fig. 6.53, ∠1 = ∠2 and ∠3 = ∠4.
(i) Is ∆ADC ≅ ∆ABC? Why?
(ii) Show that AD = AB and CD = CB.
Given: ∠1 = ∠2 and ∠3 = ∠4
Formula Used/Theory:-
→ when 2 angles and side between both the angles are equal in both the triangles then triangles are congruent by ASA congruence criterion
In ∆ADC and ∆ABC
∠1 = ∠2 (Given)
∠3 = ∠4 (Given)
AC = AC (common)
∆ADC ≅ ∆ABC
⇒ Hence; both triangles are congruent by ASA congruence
If ∆ADC ≅ ∆ABC then;
If triangles are congruent then all 3 sides of triangle are equal to all 3 sides of other triangle
AC = AC
⇒ AD = AB
⇒ CD = CB