Derive the formula for spherical mirror
According to the Cartesian system in the above figure.
Object distance (PB) = - u
Image distance (PB’) = - v
Focal length (PF) = - f
Radius of curvature (PC) = - R
From the geometry we can see that in the figure above right triangle ΔABP and ΔA’B’P’ are similar.
∴
∴ ……. (1)
Also ΔABC and ΔA’B’C’ are similar.
∴ ……. (2)
Also
From above figure
CB’ = PC – PB’ = - R - (- v) = - R + v.
And
CB = PB – PC = - u - (- R) = - - - u + R.
From (2)
∴
⇒ R (u + v) = 2uv
Dividing both sides by Ruv we get.
We know that f =
Putting this in the above equation we get
This equation is the ‘Mirror Formula’