An electric iron is rated at 230 V, 750 W. Calculate (i) the maximum current, and (ii) the number of units of electricity it would use in 30 minutes.

Question

Philoid · Accepted Answer

(a) (i) the max. current, I= PV

So, 3.260A is the max current.

(ii) the number of units of electricity it would use in 30 minute is E= P*t

So, 0.75KW*0.5h= o.375KWh.