Let k be the largest number dividing 110, 62 and 92 leaving remainders 5, 6 and 1 respectively.

Therefore, we can write 110 = ka + 5, 62 = kb + 6 and 92 = kc + 1

Where, a, b and c

110 = ka + 5 62 = kb + 6 92 = kc + 1

⇒ ka = 110 – 5 ⇒ kb = 62 – 6 ⇒ kc = 92 – 1

ka = 105 kb = 56 kc = 91

But, k is the largest number.

So, k becomes the largest divisor, g. c. d of 105, 56 and 91

105 = 5 × 3 × 7

56 = 7 × 2 × 2 × 2

91 = 7 × 13

Therefore, g. c. d(105, 56, 91) = k

g. c. d(105, 56, 91) = 7

k = 7

Therefore, the largest number dividing 110, 62 and 92 leaving remainders 5, 6 and 1 respectively is 7.