The angle of elevation of the top of a pillar from a point situated on a plane in 15°. On walking 100 m towards the pillar the angle of elevation becomes 30°. Then find the height of the pillar. (where, tan 15° = 2√3)
Let Height of the tower is BC = g.
Given, ∠CAB = 15o∠CDB = 30o AD = 100.
in ∆CAB,
………….(1)
in ∆CDB,
………….(2)
Equation (1) – Equation(2)
100 = 2g + g√3 – g√3
100 = 2g
g = 50