If the object is moved to a point only 3 cm away from the lens, what are the new position, height and nature of the image?
Height of object = 3 cm
Object distance = -3 cm
Using lens formula
Image distance (v) =- 4.8 cm; The image is formed 4.8 cm in front of the lens (on its left side); 4.8 cm high ; The nature of the image is Virtual and erect
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