We draw a triangle with length of sides 5 cm, 8 cm and 11 cm and draw a parallelogram equal in area to that triangle and having an angle 60°. [Let us write instruction process and proof]

Steps of Construction:


1. We draw a triangle ABC of given dimensions.



2. We draw a perpendicular bisector of side AB which intersects AB at D.


3. Join C to D.



4. Draw a line parallel to AB through C by completing the parallelogram ACQB.



5. From D, construct GDB=60°.


6. The line cuts parallel line through C at E.



7. From E, cut an arc of length DB on the parallel line.


8. Mark the point as F.


9. Join F to B.


10. DBFE is the required parallelogram.



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