A concave mirror of focal length 1.5m forms an image of an object placed at a distance of 40cm. Find the position and nature of the image.
According to the question;
Focal length (f) = -1.5m;
Object distance (u) = -40cm = 0.40m; (1m = 100 cm)
By mirror formula;
⇒
⇒
⇒ v = 0.5454m = 54.54cm (1m = 100 cm).
Since v = 54.54cm which is positive hence image is behind the mirror.
The image is formed at the distance of 54.54 cm behind the mirror and is virtual and erect.