A concave mirror of focal length 1.5m forms an image of an object placed at a distance of 40cm. Find the position and nature of the image.

According to the question;

Focal length (f) = -1.5m;


Object distance (u) = -40cm = 0.40m; (1m = 100 cm)


By mirror formula;









v = 0.5454m = 54.54cm (1m = 100 cm).


Since v = 54.54cm which is positive hence image is behind the mirror.


The image is formed at the distance of 54.54 cm behind the mirror and is virtual and erect.


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