A wire of resistance 20 Ω is bent to form a closed square. What is the resistance across a diagonal of the square?

Since the wire is bend in form of the square and we know that sides of square are equal so each side will have same resistance i.e 5 ohm. Now if we make diagonal two faces in each side of the diagonal will have two sides and resistance will be 10 ohm. As shown below.


So total resistance will be


Req = 5 ohm


Hence equivalent resistance is 5 ohm.


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