In a given sample of ammonia, 9g hydrogen and 42g nitrogen are present. In another sample, 5g hydrogen is present along with nitrogen. Calculate the amount of nitrogen in the second sample.
In the first sample:
9g of hydrogen and 42g of nitrogen are present. According to the law of definite proportion, hydrogen and nitrogen are present in the ratio of 9:42 i.e., 3:14
In the second sample:
It is given that 5g of hydrogen is present along with nitrogen.
According to the law of constant proportion the second sample
must also contain hydrogen and nitrogen in 3:14 ratio.
⇒ 
⇒ 14 × 5 = 3 × amt. of nitrogen
⇒ Amount of nitrogen = 70/3
⇒ Amount of nitrogen = 23.3g
Thus, the amount of nitrogen in the second sample is 23.3g.
5