Given:

Mass of sodium carbonate = 212g

Sodium carbonate is Na₂CO₃

First, we need to calculate the number of moles of sodium

carbonate we have in a 212g sample. To calculate this, we will

find the molar mass of sodium carbonate (Na₂CO₃):

⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen

⇒ 2 × 23 + 12 + 3 × 16

⇒ 46 + 12 + 48

⇒ 106g/mol

Thus, the molar mass of Na₂CO₃ is 106g/mol.

Now we will calculate total number of moles by applying the

formula given:

⇒

⇒ 2 mol

Now, we know that every mole of Na₂CO₃ have 2 moles of Na⁺ ions. Hence, total moles of Na₂CO₃ is 4 moles

Number of ions present = 6.022 × 10²³ × 4mol = 24.088 × 10²³ions