Write the ions present in

(i) Al2(CO3)3 (ii) AlBr3

i. Al2(CO3)3 : There are total two ions of Al3+ and three ions of CO32- present. Hence total no. of ions = 5


ii. AlBr3: There are total three ions of Br - and one ion of Al3+ present. Hence total no. of ions = 4


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