In a chemical reaction 10.6 g of sodium carbonate reacted with 12g of ethanoic acid. The products were 4.4 g carbon dioxide, 1.8 g of water and sodium ethanoate. The mass of sodium ethanoate formed is

Question

Philoid · Accepted Answer

Let the mass of sodium etanoate is “x”g

Acoording to law of conservation of mass,

Sum of masses of reactants = Sum of masses of products

Hence, 10.6g +12.g = x + 4.4g +1.8g

⇒ x = 16.4g

Thus, the mass of sodium ethanoate formed is 16.4g