A cyclist is moving with a speed of 14 m/s. He starts accelerating with a rate of 6 m/s 2 and acquired the speed of 18 m/s. Calculate, what distance did he move in acquiring that speed?

Question

Philoid · Accepted Answer

Using the third equation of motion: v² – u² = 2as

where: s = distance covered =?
v = final velocity = 18 m/s
u = initial velocity = 14 m/s
a = acceleration = 6 m/s²
18² – 14² = 2×6× s

324 – 196 = 12 × s
= s

s = 10.67 m

A cyclist is moving with a speed of 14 m/s. He starts accelerating with a rate of 6 m/s2 and acquired the speed of 18 m/s. Calculate, what distance did he move in acquiring that speed?

A cyclist is moving with a speed of 14 m/s. He starts accelerating with a rate of 6 m/s² and acquired the speed of 18 m/s. Calculate, what distance did he move in acquiring that speed?