In the circuit shown in figure, calculate

(i) the current through the arms AB, AC and CDE,


(ii) the potential difference across AB, CD and DE.


The equivalent resistance of the series combination is




The equivalent resistance of the parallel combination and hence circuit is given by,





If the key in the circuit is closed then only the current will flow


Total current is given by



(i)


As the circuit is in parallel combination, the current gets divided into the branches in ratio with the resistances


So the current in the branch AB is





The current in the branch AC and CDE are same as they are in parallel





(ii)


As the circuit is in parallel connection the potential difference across AB and CE are the same



Now the potential difference across CD and CE is proportional to the resistances, so





And,





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