In Fig. 5.10, if AC = BD, then prove that AB = CD.

Given: AC = BD

From the figure,


AC = AB + BC


BD = BC + CD


AB + BC = BC + CD


According to Euclid’s axiom,


When two equals are subtracted from equals, remainders are also equal.


Subtracting BC both sides,


AB + BC – BC = BC + CD – BC


AB = CD


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