In Fig. 6.15, ∠ PQR = ∠ PRQ, then prove that∠ PQS = ∠ PRT.
It is given in the question that:
∠PQR = ∠PRQ
To prove,
∠PQS = ∠PRT
Now, according to the question (from the figure)
∠PQR + ∠PQS = 180o (Linear angles pair)
⇒ ∠PQS = 180o - ∠PQR ...(i)
Similarly,
∠PRQ + ∠PRT = 180o (Linear angles pair)
⇒ ∠PRT = 180o - ∠PRQ
Now, ∠PQR = ∠PRQ (Given)
∠PRQ = 180o - ∠PQR ..,(ii)
Using (i) and (ii), we get
∠PQS = ∠PRT = 180o - ∠PQR
Therefore,
∠PQS = ∠PRT
Hence, proved