In Fig. 6.30, if AB || CD, EF CD and GED = 126°, find AGE, GEF and FGE.

It is given in the question that:

AB || CD


EF perpendicular CD


GED = 126o


Now, according to the question,


FED = 90o (EF perpendicular CD)


Now,


AGE = GED (Since, AB parallel CD and GE is transversal, hence alternate interior angles)


Therefore,


AGE = 126o


And,


GEF = GED - FED


GEF = 126o – 90o


GEF = 36o


Now,


FGE + AGE = 180o (Linear pair)


FGE – 180o – 126o


FGE = 54o


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