In Fig. 6.30, if AB || CD, EF ⊥ CD and∠ GED = 126°, find ∠ AGE, ∠ GEF and ∠ FGE.
It is given in the question that:
AB || CD
EF perpendicular CD
∠GED = 126o
Now, according to the question,
∠FED = 90o (EF perpendicular CD)
Now,
∠AGE = ∠GED (Since, AB parallel CD and GE is transversal, hence alternate interior angles)
Therefore,
∠AGE = 126o
And,
∠GEF = ∠GED - ∠FED
∠GEF = 126o – 90o
∠GEF = 36o
Now,
∠FGE + ∠AGE = 180o (Linear pair)
∠FGE – 180o – 126o
∠FGE = 54o