In Fig. 6.31, if PQ || ST, ∠ PQR = 110° and∠ RST = 130°, find ∠ QRS.
[Hint: Draw a line parallel to ST through point R.]
It is given in the question that:
PQ parallel ST,
∠PQR = 110o and,
∠RST = 130o
Construction: Draw a line XY parallel to PQ and ST
∠PQR + ∠QRX = 180o (Angles on the same side of transversal)
110o + ∠QRX = 180o
∠QRX = 70o
And,
∠RST + ∠SRY = 180o (Angles on the same side of transversal)
130o + ∠SRY = 180o
∠SRY = 50o
Now,
∠QRX + ∠SRY + ∠QRS = 180o
70o + 50o + ∠QRS = 180o
∠QRS = 60o