In Fig. 6.32, if AB || CD, ∠ APQ = 50° and∠ PRD = 127°, find x and y.
It is given in the question that:
AB parallel CD,
∠APQ = 50o and,
∠PRD = 127o
According to question,
x = 50o (Alternate interior angle)
∠PRD + ∠RPB = 180o (Angles on the same side of transversal)
127o + ∠R{B = 180o
∠RPB = 53o
Now,
y + 50o + ∠RPB = 180o (Ab is a straight line)
y + 50o + 53o = 180o
y + 103o = 180o
y = 77o