In Fig. 6.32, if AB || CD, APQ = 50° and PRD = 127°, find x and y.

It is given in the question that:

AB parallel CD,


APQ = 50o and,


PRD = 127o


According to question,


x = 50o (Alternate interior angle)


PRD + RPB = 180o (Angles on the same side of transversal)


127o + R{B = 180o


RPB = 53o


Now,


y + 50o + RPB = 180o (Ab is a straight line)


y + 50o + 53o = 180o


y + 103o = 180o


y = 77o


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