In quadrilateral ACBD,
AC = AD and AB bisects ∠ A (see Fig. 7.16). Show that Δ ABC ≅Δ ABD.
What can you say about BC and BD?
It is given in the question that:
AC = AD and,
AB bisects ∠A
To prove:
Proof: In
AB = AB (Common)
AC = AD (Given)
∠CAB = ∠DAB (AB is bisector)
Therefore,
By SAS congruence,
BC and BD are of equal length