ABCD is a quadrilateral in which AD = BC and∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) Δ ABD ≅Δ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
It is given in the question that:
AD = BC and
∠DAB = ∠CBA
(i) In
AB = BA (Common)
∠DAB = ∠CBA (Given)
AD = BC (Given)
Therefore,
By SAS congruence,
(ii) Since,
Therefore,
BD = AC (By c.p.c.t)
(iii) Since,
Therefore,
∠ABD = ∠BAC (By c.p.c.t)