Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of Δ PQR (see Fig. 7.40). Show that:
(i) Δ ABM ≅Δ PQN
(ii) Δ ABC ≅Δ PQR
It is given in the question that:
AB = PQ
BC = QR
And,
AM = PN
(i) 
BC = BM
And,
QR = QN (Am and PN are medians)
BC = QR
BC = 
QR
In 
AM = PN (Given)
AB = PQ (Given)
BM = QN (Proved above)
Therefore,
By SSS axiom,
(ii) In 
and 
AB = PQ (Given)
∠ABC = ∠PQR (By c.p.c.t)
BC = QR (Given)
Therefore,
By SAS axiom,
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