ABC is an isosceles triangle with AB = AC. Draw AP ⊥ BC to show that∠ B = ∠ C.
It is given in the question that:
AB = AC
In and
∠APB = ∠APC = 90o (AP is altitude)
AB = AC (Given)
AP = AP (Common)
Therefore,
By RHS axiom,
Thus,
∠B = ∠C (By c.p.c.t)