In Fig. 7.49, ∠ B <∠ A and ∠ C <∠ D. Show that AD < BC
It is given in the question that:
∠B < ∠A and,
∠C < ∠D
Now,
AO < BO (i) (Side opposite to the smaller angle is smaller)
OD < OC (ii) (Side opposite to the smaller angle is smaller)
Adding (i) and (ii), we get
AO + OD < BO + OC
AD < BC