ABC is a triangle. Locate a point in the interior of Δ ABC which is equidistant from all the vertices of Δ ABC.

Circum centre of a triangle is always equidistant from all the vertices of that particular triangle.

Circum centre is the point where perpendicular bisectors of all the sides of the triangle meet together.


In ∆ABC, we can find the circum centre by drawing the perpendicular bisectors of sides AB, BC, and CA of this triangle.


O is the point where these bisectors are


meeting together.


Therefore,


O is the point which is equidistant from all the vertices of ∆ABC



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