P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC)
It can be observed that ΔBQC and parallelogram ABCD lie on the same base BC and these are between the same parallel lines AD and BC
Area (ΔBQC) = Area (ABCD) (i)
Similarly,
ΔAPB and parallelogram ABCD lie on the same base AB and between the same parallel lines AB and DC
Area (ΔAPB) = Area (ABCD) (ii)
From equation (i) and (ii), we get
Area (ΔBQC) = Area (ΔAPB)