What will be the angle of deviation through a prism and 60°, when angles of incidence and emergence are 45° each?

Given: Angle of prism, A = 60o


Angle of incidence, i = 45o


Angle of emergence e = 45o


To find: Angle of deviation = D


We know


A + D = i + e


So, D = i + e – A


D = 45o + 45o – 60o


= 30o


Hence angle of deviation is 30o


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