If a line intersects two concentric circles (circles with the same centre) with centre O at A, B, C and D, prove that AB = CD (see Fig. 10.25).

Let us draw a perpendicular OM on line AD


It can be observed that BC is the chord of the smaller circle and AD is the chord of the bigger circle


We know that perpendicular drawn from the centre of the circle bisects the chord


BM = MC (i) And,


AM = MD (ii)


On subtracting (ii) from (i), we get


AM − BM = MD − MC


AB = CD


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