In Fig. 10.39, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that BEC = 130° and ECD = 20°. Find BAC.

In ΔCDE,

CDE + DCE = CEB (Exterior angle)


CDE + 20° = 130°


CDE = 110°


However, BAC = CDE (Angles in the same segment of a circle)


BAC = 110°


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