In Fig. 10.39, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find∠ BAC.
In ΔCDE,
∠CDE + ∠DCE = CEB (Exterior angle)
∠CDE + 20° = 130°
∠CDE = 110°
However, ∠BAC = ∠CDE (Angles in the same segment of a circle)
∠BAC = 110°