Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and P,Q respectively (see Fig. 10.40). Prove that ACP = QCD

Join chords AP and DQ

For chord AP,


PBA = ACP (Angles in the same segment) (i)


For chord DQ,


DBQ = QCD (Angles in the same segment) (ii)


ABD and PBQ are line segments intersecting at B


PBA = DBQ (Vertically opposite angles) (iii)


From (i), (ii), and (iii), we get


ACP = QCD


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