Derive an expression for the acceleration due to gravity on the surface of the earth. State the factors on which g depends. How does it vary with depth? Where is it maximum on the surface of the earth?

The acceleration produced in a freely falling body by the gravitational pull of the earth is called the acceleration due to gravitation.

We know that,


Force = Mass × Acceleration


F = m × a


a = …..1


Where F is the force on the object of mass m dropped from a distance r from the centre of earth of mass M.


So, force exerted by the earth on the object is


F = …..2


M = Mass of Earth


m = mass of object


r = distance of object from centre of earth


Now, from equation 1 and 2,


a =


a =


Now, from above,


a = g = Acceleration due to gravity


We also see that, although force is depending on the mass of the object,


F =


But acceleration due to gravity is independent of the mass.


g =


Factors on which g depends are:


(i) Value of gravitational constant (G)


(ii) Mass of Earth (M)


(iii) Radius of Earth (r)


As gravitational constant G and mass of earth M are always constant, so the value of acceleration due to gravity g is constant as long as the radius of earth remains constant.


At the surface of earth also, the value of g is not constant. ()


At the poles, radius of earth is minimum, hence the g is maximum. Similarly at the equator, the radius of earth is maximum, and hence the value of g is minimum. Also as we go up from the surface of the earth, distance from the centre of the earth increases and hence value of g decreases.


The value of g also decreases as we go inside the surface of earth and g is zero at the centre of earth, as at the centre of the earth the object has mass around it, so net force cancels and thus net acceleration becomes zero.


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