A boy drops a stone from a cliff which reaches on the ground in B seconds. Calculate
(i) height of cliff
(ii) final velocity of the stone
Let H be the height of the cliff.
Now, ball is initially at rest
So, u = initial velocity = 0
a = acceleration = g
v = final velocity
t = B seconds
(i) From the equations of motion, we know that,
(ii) Now, we also know that,
v = u + at
v = 0 + gB
v = gB