An object 2 cm in size is placed 20 cm in front of a concave mirror of focal length 10 cm. Find the distance from u the mirror at which a screen should be placed in order to obtain sharp image. What will be the size and nature of the image formed?

Given,

Height of object h1= 2cm


Object distance u= -20 cm


Focal length of concave mirror f= -10 cm


To find:


Distance of screen = Image distance v=???


Height of image h2=???


We know that mirror formula is:



Substituting the given values in the formula:







v = -20 cm


Screen should be placed at distance 20 cm from mirror in order to obtain sharp image


In other words, screen should be placed at distance 20+20 = 40 cm from the object in order to obtain sharp image.


Image will be formed in front of the mirror, i.e. real.





Also,




Height of image = - (Height of object)


This means that image is of same size as the object but it is inverted.


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