When an object is placed at a distance of 60 cm from a convex mirror the magnification produced is 1/2. Where should the object be placed to get a magnification of 1/3.
Given,
Object distance u1 = -60 cm
Magnification m1 = 1/2
If magnification m2 = 1/3
Then object distance u2 =???
v1 = 30 cm
We know that mirror formula is:
Substituting the given values in the formula:
So , f = 60 cm
The image must have same focal length so
Substituting the given values here:
60 v2 + 60 u2 =
60 v2 – u2v2 = -60 u2
v2 (60-u2) = -60 u2
We know that,
Substituting the above given values here:
60 – u2 = 180
– u2 = 180 – 60
– u2 = 120
u2 = -120 cm
The object should be placed at 120 cm from the mirror to get a magnification of 1/3