A person with a myopic eye cannot see objects beyond a distance of 1.5 m from it. What would be the nature and power of the corrective lens used to restore proper vision?

Since the eye is myopic, hence, the image should be formed at 1.5 m or before that on the same side as the object.


Distance of far point, v = -1.5m = -150 cm


Object distance , u = ∞


Now, to find focal length we apply the formula:





f = -150 cm


Now,


The power is given as:


Power =


The lens used is as double concave lens.


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