A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.

Let ABCD be the given trapezium whose

parallel sides are:


AB = 25m and CD = 10m


And,


Non-parallel sides are AD = 13m and BC = 14m


Now,


CM perpendicular to AB and CE ‖ AD



In


BC = 14m, CE = AD = 13m and


BE = AB – AE


= 25- 10


= 15m


Semi perimeter of =


=


= 21cm


Now,


Using Heron’s formula,


Area of =


=


=


= 84m2


1/2 *15 *CM = 84


CM = m2


Area of parallelogram AECD = Base *Altitude


= AE *CM


= = 112m2


Area of trapezium ABCD = Area of AECD + Area of triangle BCE


= (112 + 84) m2


= 196m2


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