The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g
Inner radius (r1) = 24/2 = 12 cm
Outer radius (r2) = 28/2 = 14 cm
Height (h) = Length = 35 cm
Volume = π (r22 – r12) h
= 22/7 × (142 – 122) × 35
= 110 × 52
= 5720 cm3
Mass of 1 cm3 wood = 0.6 g
Mass of 5720 cm3 wood = (5720 × 0.6) g
= 3432 g
= 3.432 kg