The diameter of a sphere is decreased by 25%. By what per cent does it’s curved surface area decrease?

Let the diameter be d

Radius (r1) =


New radius (r2) = (1 - )


= d


CSA (S1) = 4r12


= 4π ()2


= πd2


CSA (S2) = 4πr22


= 4π ()2


= d2


Decrease in surface area = S1 – S2


= πd2 - d2


= πd2


Now,


Percentage decrease = * 100


= * 100


=


= 43.75 %


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