The diameter of a sphere is decreased by 25%. By what per cent does it’s curved surface area decrease?
Let the diameter be d
Radius (r1) =
New radius (r2) = (1 - )
= d
CSA (S1) = 4r12
= 4π ()2
= πd2
CSA (S2) = 4πr22
= 4π ()2
= d2
Decrease in surface area = S1 – S2
= πd2 - d2
= πd2
Now,
Percentage decrease = * 100
= * 100
=
= 43.75 %