Prove that the following are irrationals:
(i) ![]()
(ii) ![]()
(iii) ![]()
(i) Let
is rational.
Therefore, we can find two integers p & q where, q ≠0 such that
![]()
![]()
is rational as p and q are integers.
Therefore,
is rational which contradicts to the fact that
is irrational.
Hence, our assumption is false and
is irrational.
(ii) Let
is rational.
Therefore, we can find two integers p & q where, q≠0 such that
for some integers p and q
![]()
is rational as p and q are integers.
Therefore,
should be rational.
This contradicts the fact that
is irrational.
Therefore our assumption that
is rational is false.
Hence,
is irrational.
(iii) Let
be rational.
Therefore, we can find two integers p & q where q≠0, such that
![]()
![]()
Since p and q are integers,
is also rational
Hence,
should be rational, this contradicts the fact that
is irrational.
So, our assumption is false and hence,
is irrational.