The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.
Let the shorter side of the rectangle be x m.
Then, larger side of the rectangle = (x + 30) m
Diagonal of the rectangle = 
It is given that the diagonal of the rectangle is 60 m more than the shorter side.
∴ 
= x+60
= x2 + (x+30)2 = (x+60)2
= x2 +x2 +900+60x = x2+3600+120x
= x2 – 60x – 2700 = 0
= x(x – 90 )+30(x – 90 )
=(x - 90)(x+30) = 0
= x = 90, -30
However, side cannot be negative. Therefore, the length of the shorter side will be 90 m.
Hence, length of the larger side will be (90 + 30) m = 120 m
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