Find the area of a quadrant of a circle whose circumference is 22 cm.
Let the radius of the circle be r
Circumference = 22 cm
2πr = 22

r =
= ![]()
Quadrant of circle will subtend 90° angle at the centre of the circle
Area of such quadrant of the circle =
*
* r2
=
* π * (
)2
= ![]()
= ![]()
=
cm2