A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) Minor segment


(ii) Major sector (Use π = 3.14)

Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OADB = () * r2


= () r2


= * 3.14 * 10 * 10


= 235.5 cm2


Area of minor sector OACB = * r2


= * 3.14 * 10 * 10


= 78.5 cm2


Area of ΔOAB = * OA * OB


= * 10 * 10


= 50 cm2


Area of minor segment ACB = Area of minor sector OACB -Area of ΔOAB


= 78.5 - 50


= 28.5 cm2


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