From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut andalso a circle of diameter 2 cm is cut as shown in Fig. 12.23. Find the area of the remainingportion of the square.

Each quadrant is a sector of 90° in a circle of 1 cm radius

Area of each quadrant = * r^{2}

= * * (1)^{2}

= cm^{2}

Area of square = (Side)^{2}

= (4)^{2}

= 16 cm^{2}

Area of circle = π*r*^{2} = π (1)^{2}

= cm^{2}

Area of the shaded region = Area of square - Area of circle - 4 × Area of quadrant

= 16 - - 4 *

= 16 - -

= 16 -

=

= cm^{2}

6