In Fig. 12.25, ABCD is a square of side 14 cm. With centers A, B, C and D, four circles are drawn such that each circle touch externally two of the remaining three circles. Find the area of the shaded region.

Area of each of the 4 sectors is equal to each other and is a sector of 90° in a circle of 7 cm radius

Area of each sector = * (7)^{2}

= * * 7 * 7

= cm^{2}

Area of square ABCD = (Side)^{2}

= (14)^{2}

= 196 cm^{2}

Area of shaded portion = Area of square ABCD - 4 × Area of each sector

= 196 – 4 *

= 196 – 154

= 42 cm^{2}

Therefore, the area of shaded portion is 42 cm^{2}

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