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Fig. 12.26 depicts a racing track whose left and right ends are semicircular.
The distance between the two inner parallel line segments is 60 m and they are each 106 m long. If the track is 10 m wide, find:
(i) The distance around the track along its inner edge
(ii) The area of the track.
(i) Distance around the track along its inner edge = AB + arc BEC + CD + arc DFA
= 106 + * 2πr + 106 +
* 2πr
= 212 + * 2 *
* 30 +
* 2 *
* 30
= 212 + 2 * * 30
=
= m
(ii) Area of the track = (Area of GHIJ - Area of ABCD) + (Area of semi-circle HKI - Area of semi-circle BEC) + (Area of semi-circle GLJ - Area of semi-circle AFD)
= 106 * 80 – 106 * 60 + *
* (40)2 -
*
* (30)2 +
*
* (40)2 -
*
* (30)2
= 106 (80 – 60) + * (40)2 -
* (30)2
= 106 (20) + [(40)2 – (30)2]
= 2120 + (40 – 30) (40 + 30)
= 2120 + (22/7) (10) (70)
= 2120 + 2200
= 4320 m2