Verify that y2 = 4a(x + a) is a solution of the differential equation
The differential equation is and the function to be verified as the solution is
y2 = 4a(x+a), now we need to find the value of .
Putting the value in equation,
As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation.