Verify that y2 = 4a(x + a) is a solution of the differential equation

The differential equation is and the function to be verified as the solution is

y2 = 4a(x+a), now we need to find the value of .







Putting the value in equation,


As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation.


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