In Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the
(i) Quadrant OACB
(ii) Shaded region.

(i) Since OACB is a quadrant, it will subtend 90° angle at O
Area of quadrant OACB =
*
r2
=
*
* (3.5)2
=
*
* (
)2
= ![]()
=
cm2
(ii) Area of ΔOBD =
* OB * OD
=
* 3.5 * 2
=
*
* 2
=
cm2
Area of the shaded region = Area of quadrant OACB - Area of ΔOBD
=
- ![]()
= ![]()
=
cm2