Solve the following differential equations:

Now separating variable x on one side and variable y on other side, we have



Using identities:



and on RHS side assuming ey = t, so eydy = dt by differentiating both sides.


Now integrating both sides



– log |sin(x)| = log(t+1) + c


Replacing t by ey


– log |sin(x)| = log(ey+1) + c


[sin(x)] (ey+1) = c


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