Solve the following differential equations:
Now separating variable x on one side and variable y on other side, we have
Using identities:
and on RHS side assuming ey = t, so eydy = dt by differentiating both sides.
Now integrating both sides
– log |sin(x)| = log(t+1) + c
Replacing t by ey
– log |sin(x)| = log(ey+1) + c
[sin(x)] (ey+1) = c