Solve the following differential equations:
Now separating variable x on one side and variable y on another side, we have
Adding 1 and subtracting 1 to the numerator of LHS, we get
Integrating both sides using identities:
And
Assuming ex = t and differentiating both sides we get,
exdx = dt
substituting this value in above equation
y – log(y+1) = log(1+t)
substituting t as ex
y – log(y+1) = log(1+ex) + c